Question

How many grams of chlorine are required to produce 2.00 moles of aluminum chloride

Answer 1

Answer : The mass of chlorine required are, 213 grams

Explanation : Given,

Moles of aluminum chloride = 2 moles

Molar mass of
`Cl_2` = 71 g/mole

The balanced chemical reaction of the formation of aluminum chloride will be,

`2Al+3Cl_2\rightarrow 2AlCl_3`

From the balanced chemical reaction, we conclude that

As, 2 moles of aluminium chloride obtained from 3 moles of chlorine

So, 2 moles of aluminium chloride obtained from
`(3)/(2)* 2=3mole` of chlorine

Now we have to calculate the mass of chlorine.

`\text{Mass of }Cl_2=\text{Moles of }Cl_2* \text{Molar mass of }Cl_2`

`\text{Mass of }Cl_2=3mole* 71g/mole=213g`

Therefore, the mass of chlorine required are, 213 grams