Answer:
Line LM is perpendicular to line AB. It's equation is 5y - 6x = 15
Explanation:
Given: Slope of line, AB
![(-5)/(6)](https://img.qammunity.org/2019/formulas/mathematics/high-school/k498f0a0asy61jrkic7cj29bkcbiuqimdl.png)
To find: A line which is perpendicular to given line AB
We know that if two lines are perpendicular than product of their slope is -1.
Let slope of required line is m then by using given condition we get,
![m*(-5)/(6)\,=\,-1](https://img.qammunity.org/2019/formulas/mathematics/high-school/2km3b0jj0yd5vhrjk6t8domg26j6x8j2d8.png)
![m\,=\,(6)/(5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/v1r00l290kstgkaqr5elqbujz2p8wqjjar.png)
Now we check slope of each and every line and matches with value of m.
using two point we find slope.
formula for slope,
![Slope\,=\,(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2019/formulas/mathematics/high-school/x7o9kpdgc7jju3y64bzqwm4gwb34pihwm4.png)
Coordinates of Given points are P( -5 , 4 ) , Q( 0 , -2 ) , J( -6 , 1 ) , K( 0 , -4 ) ,
L( -5 , -3 ) , M( 0 , 3 ) , N( -6 , -5 ) and O( 0 , 0 )
Slope of line PQ =
![(-2-4)/(0-(-5))\:=\:(-6)/(5))](https://img.qammunity.org/2019/formulas/mathematics/high-school/adc8esczsrhmljobt0hhvtj4gqomowyfxk.png)
Slope line JL =
![(-4-1)/(0-(-6))\:=\:(-5)/(6))](https://img.qammunity.org/2019/formulas/mathematics/high-school/2g5xjbtk4bfiufyy75gymsdezun5ntq1ka.png)
Slope line LM =
![(3-(-3))/(0-(-5))\:=\:(6)/(5))](https://img.qammunity.org/2019/formulas/mathematics/high-school/gnm62kaps3qmhmomy43gvyuosss80jyic5.png)
Slope line NO =
![(0-(-5))/(0-(-6))\:=\:(5)/(6))](https://img.qammunity.org/2019/formulas/mathematics/high-school/a5qfgrm6x0tpy3mtqvxd7622xr0ojzuv5p.png)
Thus, By comparing with above slope.
LM is our required line which is perpendicular to given Line AB.
For equation we use point-slope form,
Equation line LM
![(y-y_1)=m*(x-x_1)](https://img.qammunity.org/2019/formulas/mathematics/high-school/yzk2dnfwp85iu4io0unqyy4zxjth1uo3p9.png)
![(y-3)=(6)/(5)*(x-0)](https://img.qammunity.org/2019/formulas/mathematics/high-school/cj58sd7vk4xd77hnkkmdriqugy3di9o9at.png)
![5*(y-3)=6*(x-0)](https://img.qammunity.org/2019/formulas/mathematics/high-school/iixsoztxfdggz8y5q7vfh2d8b74wfaizt1.png)
![5y-15=6x](https://img.qammunity.org/2019/formulas/mathematics/high-school/7ivjl6wa3f14ljk1qwb6o82dtmeqtls5j7.png)
5y - 6x = 15
Therefore, Line LM is perpendicular to line AB. It's equation is 5y - 6x = 15