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A skyscraper is 396 meters tall. At a cenrtain time of day, it casts a showdow that is 322 meters long. At what angle is the sun above the horizon at that time?

User Kesarion
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2 Answers

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See image attached. There is a small right triangle formed by the skyscrapper, there is a big right triangle formed by the sun.
angle
\theta on a small and big triangle is the same.

To find the measure of the angle, use trigonometry ratio of tangent

\text{tan} \theta = \frac{\text{opposite}}{\text{adjacent}}

plug in the numbers

\text{tan} \theta = (396)/(322)

\theta = \text{tan}^(-1) \left({(396)/(322) \right)

\theta = 50.884^(0)
or approximately 50°
A skyscraper is 396 meters tall. At a cenrtain time of day, it casts a showdow that-example-1
User Bhushan Gadekar
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5 votes
do anybody know the answer to this problem
User Sanchit Kumar
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