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The points (2, r) and (6, -4) lie on a line with slope 4. Find the missing coordinate r
R=

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\text{The slope-intercept form:}\ y=mx+b\\\\\text{We have:}\ m=4\\\\\text{then}\ y=4x+b\\\\\text{The line passes through point (6; -4). Substitute:}\\\\(6;-4)\to x=6;\ y=-4\\\\-4=4\cdot6+b\\-4=24+b\ \ \ |-24\\b=-28\\\\\text{therefore:}\ y=4x-28

\text{substitute}\ (2;\ r)\to x=2;\ y=r\\\\r=4\cdot2-28=8-28=-20

Answer: r = -20
User Cwc
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