For this case suppose that we have a quadratic equation of the form:
![ax ^ 2 + bx + c](https://img.qammunity.org/2019/formulas/mathematics/high-school/9vw56qiw4jm1ap5rivu33m9mo1xf1gueh1.png)
The solution to the quadratic recuacion is given by:
![x = (-b +/- √(b^2 - 4ac))/(2a)](https://img.qammunity.org/2019/formulas/mathematics/college/edwd4ztx9g9xquwcpe2kf0b6hbqdg2uz76.png)
Where,
The discriminant is:
![b ^ 2 - 4ac](https://img.qammunity.org/2019/formulas/mathematics/high-school/81q959p2dgj3ugu3mobpzkfagtx505z7p1.png)
When the discriminant is greater than zero, then the root is positive, and therefore, we have two positive real solutions.
Answer:
B. it has two real solutions