98.1k views
5 votes
(a^2 + 3a - 18 / a^2 - 5a +6)(5a - 10 / a^2 -36)

User Reblace
by
8.5k points

1 Answer

3 votes

(a^(2)+3a-18)/(a^2-5a+6) * (5a-10)/(a^(2)-36) = ((a+6)(a-3))/((a-2)(a-3)) * (5(a-2))/((a+6)(a-6)) = (5)/(a-6) , where a \\eq 2, a \\eq 3, a \\eq +6,a \\eq -6
User Burgan
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.