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Chandra wants to know how many moles are contained in 150.0g CCl4 what quantity of CCl4 should she use to make this conversion
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Chandra wants to know how many moles are contained in 150.0g CCl4 what quantity of CCl4 should she use to make this conversion
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Dec 14, 2019
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Chandra wants to know how many moles are contained in 150.0g CCl4 what quantity of CCl4 should she use to make this conversion
Chemistry
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Md Aslam
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hey there!:
atomic mass :
C = 12.01070 amu
Cl = 35.4530 amu
Molar mass:
CCl4 = ( 1 * 12.01070 ) + ( 35.4530 *4 ) = 153.8227 g/mol
Therefore:
n = mass of solute / molar mass
n = 150.0 / 153.8227
n = 0.975 moles
hope this helps!
Kayo Lima
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Dec 20, 2019
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Kayo Lima
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