Question

A compound has an empirical formula of co3 and a molar mass of 120 g/mol. what is the molecular formula

Answer 1

To find the molecular mass, we divide the molar mass by the molar mass of
`CO_3`, round to a whole number and multiply the solution by the empirical formula.

Molar Mass of
`CO_3` =
`60.01g/mol`


`\frac {120.0g/mol}{60.01g/mol} = 1.999 =2`


`2*CO_3 = C_3O_6`

The answer is
`C_3O_6`