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If <NKL=7q+2 and m <4 =4q-5, what is m <3?

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Answer:
q = 12
m∠3 = 43°

Step-by-step explanation:
1- getting the value of q:
First we have:
∠NKL = ∠3 + ∠4 ..............> I

Now, we are given that KM bisects ∠NKL
This means that:
∠3 = ∠4 ..............>II

Substitute with II in I:
∠NKL = ∠4 + ∠4
∠NKL = 2 * ∠4 ............> III

We have:
∠NKL = 7q + 2
∠4 = 4q -5

Substitute with the givens in equation III and solve for q as follows:
∠NKL = 2 * ∠4
7q + 2 = 2(4q -5)
7q + 2 = 8q - 10
2 + 10 = 8q - 7q
q = 12

2- getting ∠3:
We know that:
∠3 = ∠4 ............> I
∠4 = 4q -5 .........> II
q = 12 ..............> III

Substitute with III in II:
∠4 = 4(12) - 5 = 43°

From I, we can deduce that:
∠3 = 43°

Hope this helps :)
If <NKL=7q+2 and m <4 =4q-5, what is m <3?-example-1
User PaulD
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