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Diameter of a sphere with the volume of 972πft^3

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\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ -----\\ V=972\pi \end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 972\pi }{4\pi }=r^3 \\\\\\ 729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}

now, recall that a diameter is twice as long as the radius, so the diameter is 2r.