Answer:
Explanation:
![y= -2x^(2)\\and\\y =x-2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/1hn2qozc0h6satv0timafqfajg14hl1dle.png)
substituting y =x-2 in equation first we get
![y= -2x^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/auu4zw3a064h6hwd1vqddhx4b1sqjslvob.png)
![(x-2)= -2x^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/52xgjrh8wdsrzmhfejbrvvpavdrlylj8f2.png)
![2x^(2)+x-2=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/69kn899d3p0tkqxfs5ay6xssv2pemqibwi.png)
solving it using quadratic formula we get
x =-1.281 and corresponding y =-3.281
for x =0.781 we have y =-1.219
more over we can graph both given and find the points of intersection from it.