1.5k views
4 votes
The quantity y varies directly with the square of x and inversely with z. When x is 9 and z is 27, y is 6. What is the constant of variation?



2

18

54

User Feather
by
6.8k points

2 Answers

2 votes

\bf \qquad \qquad \textit{double proportional variation} \\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with \underline{z}} \end{array}\implies y=\cfrac{kx}{z}\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------


\bf \stackrel{\textit{\underline{y} varies directly with the square of \underline{x} and inversely with \underline{z}}}{y=\cfrac{kx^2}{z}} \\\\\\ \textit{we also know that } \begin{cases} x=9\\ z=27\\ y=6 \end{cases}\implies 6=\cfrac{k9^2}{27} \\\\\\ \cfrac{27\cdot 6}{9^2}=k\implies 2=k
User Louis Thibault
by
6.6k points
4 votes

Answer:

2

Explanation:

User Gil SH
by
5.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.