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Timothy evaluated the expression using x = 3 and y = –4. xy-2 3x2y−4 1. (1 3 )x−1y2 2. (1 3 )3−1(−4)2 3. (1 3 )(1 31 )(−4)2 4. (1 3 )(1 3 )(−16) 5. −16 9

2 Answers

1 vote
If this is for E2020 the answer is
D)No, his value of should be positive because an even exponent indicates a positive value.
thats why it was wrong
User David Holm
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2 votes

Answer with explanation:

We have to evaluate the expression for, x=3 and y= -4 .The expression is


\rightarrow x * y^(-2) * 3 * x^2 * y^(-4)\\\\ \rightarrow 3 x^(1+2) * y^(-2-4)\\\\ \rightarrow 3 x^(3) * y^(-6)\\\\=3 (3)^3 * (-4)^(-6)\\\\=(3^4)/(4^6)\\\\ \text{used}x^a * x^b=x^(a+b)\\\\x^(-a)=(1)/(x^a)

User MdxBhmt
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6.1k points
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