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What are the roots of the given power equation? 3(x-4)^4/3 + 16 = 64 A. x=12 and x = -4 B. x=12 C. x= -4 D.x= - 12 and x = 4
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1 vote
What are the roots of the given power equation?

3(x-4)^4/3 + 16 = 64

A. x=12 and x = -4
B. x=12
C. x= -4
D.x= - 12 and x = 4

User Prabhakar Reddy
by
6.0k points

1 Answer

2 votes
Subtract 16 from both sides gives:-
3 (x - 4)^4/3 = 64 - 16 = 48
divide both sides by 3:-
(x - 4)^4/3 = 16
x - 4 = 16^3/4
x - 4 = 2^3 = 8

x = 12

ITs B



User Debasish Mitra
by
5.9k points
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