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Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0
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Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0

User Connorelsea
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1 Answer

4 votes
Hello,
center is (4,-6)
radius=4
since

x^2-8x+y^2+12y+36=0\\ x^2-2*4x+16-16+y^2+2*6y+36=0\\ (x-4)^2+(y+6)^2=4^2


User Hilydrow
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