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When 9^2/3 is written in simplest radical form, which value remains under the radical?

User Lykegenes
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2 Answers

5 votes

Answer:3

Explanation:

User GuerillaNerd
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3 votes
First, change 9 into exponential form. 9 equals 3 squared. We change 9 into smaller number to find the simplest form of the radical later.

9^{(2)/(3)}

=(3^(2))^{(2)/(3)}

=3^{(4)/(3)}

Second, change into radical form
The denominator of fractional exponent is the root of the radical

3^{(4)/(3)}

= \sqrt[3]{ 3^(4)}

Third, simplify the exponential form under the radical using exponential property

= \sqrt[3]{ 3^(3+1)}

= \sqrt[3]{3^(3) * 3^(1)}

= \sqrt[3]{3^(3)} * \sqrt[3]{3}

= 3 * \sqrt[3]{3}

= 3 \sqrt[3]{3}

In the simplest radical form, what remains under the radical is 3
User SweSnow
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