Question

Check my answers please!!!!!! I think the special right triangle 30 -60 -90 would be used. For the height of the triangle I had got 10√3 cm. for the area I got 50√3 cm. The image of the question is down below, thanks!

Answer 1

THE HEIGHT
To find the height, use trigonometry ratio (tan) of 60°

`\frac{\text{opposite}}{\text{adjacent}}` = tan α

plug in the numbers

`(height)/(10)` = tan 60°

`(height)/(10)` = √3
move 10 to the right side
height = 10√3

The height is 10√3 cm

THE AREA
To determine the area of a triangle, use the following formula

`\boxed{a= (1)/(2) * b * h }`
b stands for the base, h stands for the height

plug in the numbers
a = 1/2 × b × h
a = 1/2 × 10 × 10√3
a = 5 × 10√3
a = 50√3

The area is 50√3 cm²