Question

a car traveling at 36 m s starts to decelerate Stanley it comes to a complete stop in 9 seconds what is its acceleration

Answer 1

The equation of movement of the car is given by:

`vf = a * t + vo`
Where,
vf: final speed
a: acceleration
t: time
vo: initial speed
By the time the car stops we have:

`vf = 0`
Substituting values we have:

`0 = a * 9 + 36`
Clearing the acceleration we have:

`a = -36/9 a = -4 m / s ^ 2`
Answer:
its acceleration is:

`a = -4 m / s ^ 2`

Answer 2

The answer is -4 m/s². A car traveling at an initial velocity of 36 meter per second starts to decelerate and then suddenly the car comes to a complete stop which means the final velocity is zero. The acceleration can be calculated as
acceleration = (final velocity - initial velocity) / time interval
= (0 m/s - 36 m/s) / 9s
= -4 m/s²