Question

What is the momentum of a photon that has a wavelength of 3.00 102 nm? remember the wavelength of a photon is equal to planck's constant divided by the photon's momentum?

Answer 1

The momentum of a photon with a wavelength of 3.00x10^2 nm is 2.21x10^-27 kg.m/s.

Step-by-step explanation:

The momentum of a photon can be calculated using the equation:

p = h/λ

where p is the momentum, h is Planck's constant (6.63x10-34 J-s), and λ is the wavelength. Given a wavelength of 3.00x102 nm, we can convert it to meters by dividing by 109 (1 nm = 10-9 m).

λ = 3.00x102 nm x (1 m/109 nm) = 3.00x10-7 m

Substituting the values into the equation:

p = (6.63x10-34 J-s) / (3.00x10-7) = 2.21x10-27 kg.m/s

Answer 2

de Broglie's equation is used to show that photons have both particle and wave nature. photons are quantized packets of energy. the wave nature of photons can be proven as they have a wavelength. the particle nature is given by them having both velocity and mass.
de Broglies equation is;
λ = h / p
where λ - wavelength
h - Planck's constant
p - momentum
substituting the values in the equation
p = h/λ

`p = (6.626 * 10^(-34)m^(2) kg/s )/(3.00 * 10^(-7) m)`
p = 2.20 x 10⁻²⁷ kgm/s
momentum of photon is 2.20 x 10⁻²⁷ kgm/s