The motion of the light is a uniform motion with constant speed
![v=3 \cdot 10^5 km/s](https://img.qammunity.org/2019/formulas/physics/high-school/ovv7bw27fih3jpuppm4hdkalqn42attv46.png)
, therefore we can use the basic relationship between speed, space and time:
![v= (S)/(t)](https://img.qammunity.org/2019/formulas/physics/high-school/6aaujfki6am79susk34mpndxor2140992q.png)
(1)
where S is the distance covered and t is the time taken. The light takes t=1.3 s to travel from the moon to Earth, therefore by rearranging eq.(1) we can find the distance between the Moon and the Earth:
![S=vt=(3 \cdot 10^5 km/s)(1.3 s)=390000 km=3.9 \cdot 10^5 km](https://img.qammunity.org/2019/formulas/physics/high-school/n29o7brb2k4pm53no8fqrfuzr26cmn01ky.png)