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Given the unbalanced equation: ___ca(oh)2 + ___(nh4)2so4 → ___caso4 + ___nh3 + ___h2o what is the sum of the coefficients when the equation is completely balanced using the smallest whole-number coefficients?
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Given the unbalanced equation: ___ca(oh)2 + ___(nh4)2so4 → ___caso4 + ___nh3 + ___h2o what is the sum of the coefficients when the equation is completely balanced using the smallest whole-number coefficients?

User Gisell
by
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2 Answers

5 votes

Answer:

7

Step-by-step explanation:

User Randal
by
8.8k points
7 votes
Ca(OH)2 + (NH4)2SO4 → CaSO4 + 2NH3 + 2H2O

That is the balanced equation.

The coefficients represent the amount of moles for that reactant. There is 1 mole of Calcium Hydroxide, 1 mole of Ammonium Sulfate, 1 mole of Calcium Sulfate, 2 moles of Ammonium, and 2 moles of water.

Now add all the coefficients/moles.


1+1+1+2+2= 7

The answer is 7 coefficients.
User Netgirlk
by
8.2k points
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