Question

In the reaction h2so4 + na2co3 → na2so4 + co2 + h2o 14.5 g of water is collected. what is the molarity of sulfuric acid if 1.78 l were used in the reaction? 1. 146 m 2. 0.453 m 3. 1.43 m 4. 0.697 m 5. 1.78 m6. 0.0046 m

Answer 1

H2SO4 + Na2CO3 → Na2SO4 + CO2 + H2O

The molarity of sulfuric acid if 1.78 L were used in the above reaction is
0.453 M (answer 2)

Calculation
find the moles of water produced = mass/molar mass

= 14.5 g /18 g/mol = 0.806 moles

by use of of mole ratio between H2So4 to H2O which is 1:1 the moles of H2SO4 is also = 0.806 moles


Molarity of H2SO4 is therefore = moles/volume in liters

= 0.806 mol/ 1.78 L = 0.453 M (answer 2)