Question

A 3.0 l container holds a sample of hydrogen gas at 300 k and 100 kpa. if the pressure increases to 400 kpa and the volume remains constant, what will the temperature be? question 17 options:

Answer 1

1200k

Step-by-step explanation:

Answer 2

The temperature will be 1200K if the volume remained constant

calculation
This is calculated using gay lussac law formula, that is P1/ T1=P2/T2 since the volume is constant
P1 = 100 Kpa
T1= 300 K
P2= 400 Kpa
T2=?

by making T2 the subject of the formula T2 =( P2 xT1)/P1

T2 is therefore = (400 KPa x 300 K) / 100 Kpa = 1200 K