Computer A can carry out analysis in 6 hours. That means in an hour, computer A does
![(1)/(6)](https://img.qammunity.org/2019/formulas/mathematics/college/yy8097piiceo70bmsp5buca3g8bbyn2qmy.png)
of the job.
Computer B can carry out analysis in 4 hours. That means in an hour, computer B does
![(1)/(4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/55daype98oi47j2b5nw9r26vt4buk0otmp.png)
of the job.
If both computers work together, in an hour they do:
![(1)/(6)+ (1)/(4)](https://img.qammunity.org/2019/formulas/mathematics/college/2wfsrgq7furcoyos10q44xl4jjwwr6xgk5.png)
![= (2)/(12)+ (3)/(12) \text{(equalize the denominators)}](https://img.qammunity.org/2019/formulas/mathematics/college/zzznayhadrnalzb9l05kqz0yk48ah45amw.png)
![= (5)/(12)](https://img.qammunity.org/2019/formulas/mathematics/college/hho2k8dfu0qt6sfaltiw5mszjifv72cuqr.png)
In an hour, they do
![(5)/(12)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/b0v043n01ysq6y6s56fw3o72zcqd4j3jli.png)
of the job.
To finish the job, they need
![(12)/(5)](https://img.qammunity.org/2019/formulas/mathematics/college/slifln884bfnv2s80mh2xr4gen2vyouukv.png)
hours.
![(12)/(5)](https://img.qammunity.org/2019/formulas/mathematics/college/d0gexof5eoy95l4ijuzov39j7aghhfk77e.png)
hours
= 2.4 hours
= 2 hours + 0.4 hour
= 2 hours + 0.4 × 60 minutes
= 2 hours 24 minutes
They finish analysing in 2 hours 24 minutes