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a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together and twice as many dimes as nickels, how many of each kind of coin are there?
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a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together and twice as many dimes as nickels, how many of each kind of coin are there?

User LiamNeesonFan
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2 Answers

4 votes

Answer:DDDD

Explanation:

a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together-example-1
User Henri Hietala
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7.2k points
4 votes
For this case, the first thing we must do is define variables:
x: number of nickels
y: number of dimes
z: number of quarters
We now write the system of equations:

0.05x + 0.10y + 0.25z = 6 x + y + z = 52 y = 2x
Solving the system of equations we have:

x = 14 y = 28 z = 10
Answer:
14 nickels
28 dimes
10 quarters
User SolidSun
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7.8k points
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