Question

a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together and twice as many dimes as nickels, how many of each kind of coin are there?

Answer 1

Answer:DDDD

Explanation:

Answer 2

For this case, the first thing we must do is define variables:
x: number of nickels
y: number of dimes
z: number of quarters
We now write the system of equations:

`0.05x + 0.10y + 0.25z = 6 x + y + z = 52 y = 2x`
Solving the system of equations we have:

`x = 14 y = 28 z = 10`
Answer:
14 nickels
28 dimes
10 quarters