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if you Launch a cannonball at a launch angle of 55° and an initial speed of 30m/s. What is the cannonball's range?

User Fabrizio Fenoglio
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1 Answer

17 votes
17 votes

Answer:

86.2 m range

Step-by-step explanation:

Vertical component of initial shot = 30 sin 55= 24.575 m/s

Now you can find out for how long it is in the air

when it hits the ground , position = 0

0 = 24.575 t - 1/2 ( 9.81) t ^2

finds t = 5.01 seconds (Using quadratic formula)

HORIZONTAL component = 30 cos 55 = 17.21 m/s

it travels this speed for 5.01 seconds

5.01 * 17.21 = 86.2 m

User M Falanga
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