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Let ​ f(x)=x2−16x+71 ​ .what is the vertex form of f(x)?what is the minimum value of f(x)? enter your answers in the boxes.
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Let ​ f(x)=x2−16x+71 ​ .what is the vertex form of f(x)?what is the minimum value of f(x)? enter your answers in the boxes.

User QuadX
by
8.7k points

2 Answers

0 votes

Answer:

(x+8)2+7

Explanation:

User Elad Benda
by
8.8k points
4 votes
Your vertex is (8,7)

First find the x intercept
-2/2a

X = 16/2
X = 8

Substitute the value x and solve for y
Youd get 7

Hence
(8,7)
User Hartator
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