Find the s10 for series 2+7+12+17+

asked Dec 22, 2019 211k views

3 votes

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5 votes

sn=n/2(2a+(n-1)d)
n=10 a=2 d=5

s10=10/2(2*2+(10-1)5)
=5(4+9*5)
=5(4+45)
=5(49)
=245

answer should be 245.

hope this helps!

Pravin Poudel answered Dec 27, 2019

6.1k points

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