Answer:
Changes the sign of the measured electrical potential
Step-by-step explanation:
If you have a positive test charge
with an electric field, and it moves from point A to point B, keeping the balance without exception, then the work that the agent that carries the load has to do is equal to:
![V_B-V_A=V_B_A=(W_A_B)/(q_o)](https://img.qammunity.org/2019/formulas/advanced-placement-ap/college/nwxcsn74m0q6cke9swc3512ld1d6q3y6d0.png)
Which is called electric potential difference.
This work can be a negative, positive or null value, and the electric potential corresponding to B is less, greater or equal respectively to the potential of A.
On a VOM digital multimeter the black color is always connected inside the pin or connector marked COM, short for COMMON (Common/Ground/0 V) and the red tip is connected inside the V pin (Highest electrical potential )
Let:
![V_B=Highest\hspace{3} electrical\hspace{3} potential\\V_A=Lowest\hspace{3} electrical\hspace{3} potential](https://img.qammunity.org/2019/formulas/advanced-placement-ap/college/zs1yxchyecgsa4hr8hch1ri0suoh67ak6h.png)
Also, let's assume:
![V_B=12V\\V_A=1](https://img.qammunity.org/2019/formulas/advanced-placement-ap/college/1qew22tt4r5084j27nqv44n4988l64gj84.png)
So, if you meaure the voltage with the correct polarity, the VOM will show you this result:
![V_B-V_A=V_B_A=12-1=11V](https://img.qammunity.org/2019/formulas/advanced-placement-ap/college/1c9z4gk7j5mfs97qawqx72ov4vy56guy6h.png)
On the other hand if you make a mistake in polarity, the VOM will show you the same result but with a different sign:
![V_A-V_B=V_A_B=1-12=-11V](https://img.qammunity.org/2019/formulas/advanced-placement-ap/college/trxzk4fmi9f3wsmwss2moe83vwk37xt89t.png)