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A foul ball leaves the end of a baseball bat and travels according to the formula

h(t) = -16t? +64t where h is the height of the ball in feet and t is the time in seconds.
How long will it take for the ball to reach a height of 64 feet in the air?

1 Answer

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Final answer:

To find the time it takes for the ball to reach a height of 64 feet, we can set the equation h(t) = 64 and solve for t using the quadratic formula. The two solutions are t = 0.54 seconds and t = 3.79 seconds. Since we are looking for the longer time, the ball will take approximately 3.79 seconds to reach a height of 64 feet in the air.

Step-by-step explanation:

To find the time it takes for the ball to reach a height of 64 feet, we need to set the equation h(t) = 64 and solve for t.

The equation given is h(t) = -16t^2 + 64t, where h is the height of the ball in feet and t is the time in seconds.

Plugging in 64 for h, we get 64 = -16t^2 + 64t.

This is a quadratic equation which we can solve using the quadratic formula.

Using the quadratic formula, we find that the two solutions are t = 0.54 seconds and t = 3.79 seconds.

Since we are looking for the time it takes for the ball to reach a height of 64 feet, we take the longer solution, which is t = 3.79 seconds.

Therefore, it will take the ball approximately 3.79 seconds to reach a height of 64 feet in the air.

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