Question

Light traveling through air at 3.00 · 108 m/s. reaches an unknown medium and slows down to 2.00 · 108 m/s. what is the index of refraction of that medium

Answer 1

We ratio the speeds for refractive Index n Largest goes on the top
3 x 10^8/2x10^8= 1.5
n = 1.5

Answer 2

Answer: The refractive index of the unknown medium is 1.5

Step-by-step explanation:

To calculate the refractive index of the medium, we use the equation:

`\eta=(c)/(v)`

where,

`\eta` = refractive index of medium = ?

c = speed of light in air =
`3.00* 10^8m/s`

v = speed of light in medium =
`2.00* 10^8m/s`

Putting values in above equation, we get:

`\eta =(3.00* 10^8m/s)/(2.00* 10^8m/s)\\\\\eta=1.5`

Hence, the refractive index of the unknown medium is 1.5