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Find the exact value of tan(θ + φ) given that sin θ = 4/5 and sin φ = 5/13and that θ and φ are between 0 and π/2. Note these angles are Pythagorean Triples.

User Omg
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2 Answers

3 votes

Final answer:

The exact value of tan(θ + φ) is 7/4; found using the angle sum identity for tangent after calculating the cosines of θ and φ from their sines considering they are in the first quadrant and constitute Pythagorean triples.

Step-by-step explanation:

To find the exact value of tan(θ + φ), given that sin θ = 4/5 and sin φ = 5/13, with both angles between 0 and π/2 and being Pythagorean triples, we will use trigonometric identities and Pythagorean relationships.

First, let's find the cosines of the angles using the Pythagorean theorem. Since sin θ = 4/5, we can determine that cos θ = √(1 - sin2 θ) = √(1 - (4/5)2) = √(1 - 16/25) = 3/5, knowing that θ is in the first quadrant where cosine is positive. Similarly, since sin φ = 5/13, cos φ = √(1 - sin2 φ) = √(1 - (5/13)2) = 12/13.

Now we will use the angle sum identity for tangent, which is tan(θ + φ) = (tan θ + tan φ)/(1 - tan θ tan φ).

We know tan θ = sin θ/cos θ = (4/5)/(3/5) = 4/3 and tan φ = sin φ/cos φ = (5/13)/(12/13) = 5/12.

Plugging these into the identity gives us

tan(θ + φ) = (4/3 + 5/12)/(1 - (4/3 * 5/12))

= (16/12 + 5/12)/(1 - 20/36)

= 21/12 / (16/36)

= (21/12) * (36/16)

= 7/4.

The exact value of tan(θ + φ) is 7/4.

User Ronye Vernaes
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4 votes

\sin\theta=\frac45\implies\cos\theta=\frac35

\sin\varphi=\frac5{13}\implies\cos\varphi=(12)/(13)



\tan\theta=(\sin\theta)/(\cos\theta)=\frac45

\tan\varphi=(\sin\varphi)/(\cos\varphi)=\frac5{12}


\tan(\theta+\varphi)=(\tan\theta+\tan\varphi)/(1-\tan\theta\tan\varphi)=(63)/(16)
User Will Decker
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5.1k points