Question

a man who weighs approximately 140 pounds has two,12 ounce beers and one 1 1/2 oz. shots of liquor in one hour. what is his estimated BAC?

Answer 1

If you meant one 1/2 oz shot of liquor in one hour then his estimated BAC would be 0.09

Answer 2

His estimated BAC is 0.08

Explanation:

To calculate the BAC (Blood Alcohol Content) we first find the amount of alcohol (in grams) of the drinks.

In the US, a standard drink has 14 g of alcohol. The man has 2 beers and 1 shot; this is 3 standard drinks:

3 × 14 = 42 g of alcohol.

Next we convert the weight in pounds to grams. 1 pound = 453.592 grams

We do this by multiplying by 454:

140 × 454 = 63560

Next we multiply by the gender constant. For men, this is 0.68:

63560(0.68) = 43220.8

We divide the grams of alcohol by this number:

42 ÷ 43220.8 = 0.000972

Multiply this by 100:

0.000972(100) = 0.0972

This is the BAC right after drinking. To account for the time that has passed, we multiply the number of hours by 0.015:

1 × 0.015 = 0.015

We subtract this from our immediate BAC:

0.0972 - 0.015 = 0.0822 ≈ 0.08

His estimated BAC is 0.08