Question

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. The roots of an equation are x = -1 ± i. The equation is x2 + + 2 = 0.

Answer 1

If those are your roots, in factorization form they are [x-(-1+i)][x-(-1-i)], which simplifies to (x+1-i)(x+1+i). FOIL that out like you would anything else to get the mess that looks like this:
`x^(2) +x+ix+x+1+i-ix-i- i^(2)`. Putting things in order makes it easier to deal with.
`x^(2) +x+x+ix-ix+i-i+1- i^(2)`. Canceling out what we can, gives us
`x^(2) +2x+1- i^(2)`.
`i^(2)=-1`. That simplifies to
`x^(2) +2x+1-(-1)`, which of course gives us
`x^(2) +2x+1+1` and
`x^(2) +2x+2` is the final result. Your missing term there is 2x