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A boat has a speed of 15 mph in still water. it travels downstream from greentown to glenavon in g hours. it then goes back upstream from glenavon to cambria, which is 2 miles downstream from greentown, in g hours. find the rate of the current.

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a boat has a speed of 15 mph in still water. It travels downstream from Greentown, in three-fifths of an hour. It then goes back upstream from Glenavon to Cambria, which is two miles downstream from Greentown, in three fithts of an hour. Find the rate of the current.

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Let rate of the current be "c".

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Downstream DATA:

Time = (3/5) hr ; distance = x miles ; Rate = x/(3/5)= 5x/3 mph

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Upstream DATA:

Time = (3/5)hr ; distance= x-2 miles ; Rate = (x-2)/(3/5) = 5(x-2)/3 mph

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EQUATIONS:

Rate downstream: 15+c = 5x/3

Rate upstream : 15-c = 5(x-2)/3


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Add to get: 30 = [5x/3] + [5(x-2)/3]

Multiply thru by 3 to get:

5x + 5(x-2) = 90

10x=100

x = 10 miles

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Substitute into 15+c = 5x/3 to solve for "c":

15+c = 50/3

c = 50/3 - 45/3 = 5/3 mph

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Rate of the current is (5/3) mph

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Cheers,

Vasu J



User Nico Schertler
by
9.0k points
2 votes
Answer

rate of current = (1/x) mph

Step-by-step explanation
let the distance from Greentown to Glenavon be y miles and the rate of current be x mph.

y = (15+x)g
y = 15g+gx .........................................(1)

The distance from Glenavon to Cambria = (y-2)

y-2 =(15-x)g
y-2 = 15g-gx
y = 15g - gx + 2 ....................... (2)

equation equation (1) and (2)

15g + gx = 15g - gx + 2
2gx = 2

dividing by 2g both sides we get,

x = 1/2g mph
User BVa
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