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What is the solution to the system of equations? {10x^2 - y = 48 2y = 16x^2 + 48

User Rea Haas
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A graph shows the solutions to be
(x, y) = (-6, 312) or (6, 312)


To solve algebraically, remove a factor of 2 from the second equation and use that expression to substitute for y in the first equation.
10x^2 -(8x^2 +24) = 48
2x^2 = 72
x = ±√(72/2) = ±6
y = 8*36 +24 = 312
What is the solution to the system of equations? {10x^2 - y = 48 2y = 16x^2 + 48-example-1
User Rick Gladwin
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