Question

Slope and point of 3y=x+11

Answer 1

point slope form is
`(y-y_1)=m(x-x_1)` where
`(x_1,y_1)` are a point that the line passes through and
`m` is the slope
I guess solve for 1 y and get the constants to the left side3y=x+11divide both sides by 3
`y=(1)/(3)(x+11)`there you have it:
`y-0=(1)/(3)(x-(-11))`it passes through the point (-11,0) and has a slope of 1/3

Answer 2

Slope formula is y = mx + b

Isolate the y. Divide 3 from both sides

3y = x + 11

(3y)/3 = (x + 11)/3

y = (x + 11)/3

Set y = 0.

0 = (1x + 11)/3

Slope = 1/3

Solve for x.

0(3) = (x + 11)/3(3)

0 = x + 11

0 (-11) = x + 11 (-11)

x = 0 - 11

x = 11

hope this helps