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Find the value of n such that x2 – 11x + n is a perfect square trinomial.

2 Answers

4 votes
n = 121/4

(x - 11/2)^2
x^2 - 11x + 121/4
User Evoskuil
by
7.6k points
4 votes

Answer:


n=(121)/(4)

Explanation:

Given:
x^2-11x+n

The given expression is perfect square trinomial.

The middle term is negative.


a^2-2ab+b^2=(a-b)^2


\Rightarrow x^2-11x+n


\Rightarrow x^2-11x+n=a^2-2ab+b^2

Compare both sides


a=x


2ab=11x


b^2=n

Using three equation to solve for n


2xb=11x
\because a=x


b=(11)/(2)

Now, we will put b


n=b^2


n=((11)/(2))^2


n=(121)/(4)

Hence, The value of n is 121/4 which makes perfect square trinomial.

User Avim
by
8.2k points

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