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Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.

1.2
1.3
0.78

User MadProfit
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1 Answer

4 votes
The equivalent resistance of three resistors in series is given by the sum of the resistances:

R_(eq)=R_1+R_2+R_3
In this circuit, the value of the three resistances is:

R_1=3 \Omega

R_2=4 \Omega

R_3=5 \Omega
Therefore, the equivalent resistance of the circuit is:

R_(eq)=3 \Omega+4 \Omega + 5 \Omega =12 \Omega
User Adam Fletcher
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