Question

Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.

1.2
1.3
0.78

Answer 1

The equivalent resistance of three resistors in series is given by the sum of the resistances:

`R_(eq)=R_1+R_2+R_3`
In this circuit, the value of the three resistances is:

`R_1=3 \Omega`

`R_2=4 \Omega`

`R_3=5 \Omega`
Therefore, the equivalent resistance of the circuit is:

`R_(eq)=3 \Omega+4 \Omega + 5 \Omega =12 \Omega`