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A group consists of 10 men and 11 women. in how many ways can a team of exactly 4 men and 6 women be selected?

User DMKE
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1 Answer

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C(10,4)×C(11,6) = 210×462 = 97,020

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Any of the choices of 4 of 10 men can be combined with any of the choices of 6 of 11 women. The "n choose k" function, C(n, k) is computed as n!/(k!×(n-k)!).
User Sanghyun
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