Answer : The percent composition of nitrogen in
is, 46.7 %
Explanation : Given,
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Molar mass of O = 16 g/mole
Molar mass of N = 14 g/mole
First we have to calculate the molar mass of
.
Molar mass of glucose
=
![1(12)+1(16)+2(14)+4(1)=60g/mole](https://img.qammunity.org/2019/formulas/chemistry/high-school/8byihiu3j45v7l5hhe73t3m1uwwmf3d6px.png)
Now we have to calculate the mass percent composition of nitrogen in
.
As we now that there are 1 number of carbon atom, 4 number of hydrogen atoms, 1 number of oxygen atom and 2 number of nitrogen atoms.
The mass of nitrogen =
![2* 14=28g](https://img.qammunity.org/2019/formulas/chemistry/high-school/3c4gcxzq92u62dbhts0w08wkwlclazdl4w.png)
Formula used :
![\%\text{ Mass percent composition of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Molar mass of } CO(NH_2)_2}* 100](https://img.qammunity.org/2019/formulas/chemistry/high-school/df8pl98ncdmpn60job8yxzcunvhmcrlbc9.png)
Now put all the given values in this formula, we get:
![\%\text{ Composition of nitrogen}=(28)/(60)* 100=46.7\%](https://img.qammunity.org/2019/formulas/chemistry/high-school/kzkedg5q2o9v09s7u5hcay668g4v9i8wrl.png)
Therefore, the percent composition of nitrogen in
is, 46.7 %