we have that
A (2,-3)
B (-3,-4)
C (-4,2)
D (2,4)
E (3,1)
F(-2,3)
using a graph tool
see the attached figure N 1
Part A: Using the graph above, create a system of inequalities that only contains points A and E in the overlapping shaded regions.
A (2,-3) E (3,1)
y<= 1
x>=2
is a system of a inequalities that will only contain A and E
to graph it, I draw the constant y = 1 and x=2 and the shaded part is below y=1 and to the right of x=2
see the attached figure N 2
Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A
we know that
the system of a inequalities is
y<= 1
x>=2
the solution is
domain
all x real numbers belonging to the interval [2,∞)
and
range
all y real numbers belonging to the interval (-∞,1]
therefore
if points A and E are solutions both points must belong to the domain and range interval
point A (2,-3)
2 is included in the interval [2,∞)
-3 is included in the interval (-∞,1]
point E (3,1)
3 is included in the interval [2,∞)
1 is included in the interval (-∞,1]
therefore
both points are solution
Part C: Chickens can only be raised in the area defined by y > 2x-2. Explain how you can identify farms in which chickens can be raised
step 1
graph the inequality y > 2x-2
see the attached figure N 3
the farms in which chickens can be raised are the points B, C, D and F
are those that are included in the shaded part