200k views
5 votes
The standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→li(s) −3.04 cl2(g)+2e−→2cl−(aq) +1.36 in a galvanic cell, the two half-reactions combine to 2li(s)+cl2(g)→2li+(aq)+2cl−(aq) calculate the cell potential of this reaction under standard reaction conditions. express your answer with the appropriate units. e∘ = submithintsmy answersgive upreview part

User Dumbo
by
5.7k points

1 Answer

2 votes
Li+(aq) +e- →Li (s) - 3.04
Cl2(g) + 2e- → 2Cl-(aq) +1.36

over all equation
2Li(s) + Cl2(g) →2 Li+(aq) + 2Cl-(aq)
The cell potential of this reaction is + 4.40 V

calculation
Ecell =E cathode - E anode
E cathode is = + 1.36 v
E anode is = - 3.04 V

therefore E cell= 1.36 -(-3.04 ) = 4.40 V



User Cwarny
by
5.6k points