Question

What is the volume of 2 mol of chlorine gas at STP?

Answer 1

The conversion factor for volume at STP is
`\frac {1mol}{22.4L}` or \frac {22.4L}{1mol}. Since we want volume, we would use \frac {22.4L}{1mol}. We conclude with the following calculations:


`2molCl_(2)*\frac {22.4LCl_(2)}{1molCl_(2)} = 44.8L Cl_(2)`

The answer is 44.8L Cl2

Answer 2

Volume of 2 mol of chlorine gas at STP is 44.8 L

Step-by-step explanation:

Let us assume chlorine gas behaves ideally.

According to law of ideal gas- PV=nRT

where P is pressure of gas, V is volume of gas, n is number of moles of gas, R is gas constant and T is temperature in Kelvin.

At STP, P is 1 atm and T is 273 K

Here n=2 and R=0.082 L.atm/mol.K

So
`V=(nRT)/(P)=(2* 0.082* 273)/(1)L=44.8 L`

Hence volume of chlorine gas at STP is 44.8 L