Question

A gas sample exerts a pressure of 1.2 atm at 18ºc and a volume of 3.94 l. what is the new volume at stp

Answer 1

we can use the combined gas law equation for this question.

`(PV)/(T) = k`
where P - pressure
V - volume
T - temperature in kelvin
and k is constant
therefore

`(P1V1)/(T1) = (P2V2)/(T2)`
parameters for the STP conditions are on the left side and parameters for the given instance
T1 - standard temperature - 273 K
T2 - 18 °C + 273 = 291 K
P1 - standard pressure - 1 atm
substituting the values in the equation

`(1 atm * V)/(273K) = (1.2 atm*3.94L)/(291K)`
V = 4.4 L
new volume STP is 4.4 L