Question

What is the slope-intercept form equation of the line that passes through (3,4) and (5,16)?

Answer 1

First, find the slope between the two points (3, 4) & (5, 16):
m =
`( y_(2) - y_(1) )/( x_(2) - x_(1) )`
=
`( 4 -16)/( 3 - 5)`
=
`(-12)/( -2)`
= 6

Then, input the slope and one of the points into the point-slope form:
y -
`y_(1)` = m(x -
`x_(1)`)
y - 4 = 6(x - 3)
y - 4 = 6x - 18
y = 6x - 18 + 4
y = 6x -14

Answer: y = 6x - 14