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How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N 0.04 moles 0.08 moles 0.12 moles 0.48 moles 0.72 moles
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How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N 0.04 moles 0.08 moles 0.12 moles 0.48 moles 0.72 moles
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6 Li + N2 = 2 Li3N
6 moles Li ------------ 2 moles Li3N
0.24 moles Li ------- moles Li3N
moles Li3N = 0.24 *2 / 6
moles Li3N = 0.48 / 6 => 0.08 moles
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Jul 27, 2019
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