I think you mean circumference...Area is
![A= \pi r^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/g7edsuqma4l537ot5s0b6gm9jmckeeg5w2.png)
. We have the area so we need to use it to solve for the radius which we will then use in the circumference formula.
![16 \pi = \pi r^(2)](https://img.qammunity.org/2019/formulas/mathematics/college/jsthphqwbryyr92134tprwalm2xq0xb50d.png)
. Divide both sides by pi to get
![(16 \pi )/( \pi ) = r^(2)](https://img.qammunity.org/2019/formulas/mathematics/college/rss0dd1tia5h6o9758uczyk1u16zly6qyp.png)
. Of course the simplification of the left side gives us
![16= r^(2)](https://img.qammunity.org/2019/formulas/mathematics/college/xmrqairxfxuv5h64rs1zym2m5qd5odn082.png)
and r = 4. Now fill that in to the circumference formula, which is
![C=2 \pi r](https://img.qammunity.org/2019/formulas/social-studies/high-school/n1na47c5s7k8kv8qc52zs8kdtj6pewdohl.png)
, to get C
![C=2 \pi (4)](https://img.qammunity.org/2019/formulas/mathematics/college/8cefc98osi04cluecnpayxmrumzhgkn592.png)
which is a circumference of
![8 \pi](https://img.qammunity.org/2019/formulas/mathematics/college/is4onu8bcvuv3e304t4btkzea0uiytkkve.png)