The correct answer is d.We have the following system of linear equations:
(I)

(II)

Let's use the elimination method, then let's multiply the equation (1)

and subtracting (I) and (II):
(I)

∴

(I)

(II)

____________________
(III)

∴

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

∴

∴

∴

∴

Let's substitute the values of x and y into (I) and (2)
(I)

(II)

Finally the answer is:
