Question

if a gas is initially at 5.50 atm, 121 L, 293 K, then it changes to 5.15 atm and 298 K, what is the new volume?

Answer 1

The new volume of the gas is 131.43 liters

calculation

This is calculated by use of combined gas law equation

that is p1V1/T1 = P2V2/T2

P1 = 5.50 atm
V1= 121 L
T1= 293 k
P2= 5.15 atm
T2 = 298 K
V2 =?

by making V2 the subject of the formula

V2= T2 P1V1/ P2T1


V2 is therefore = (298 k x 5.50 atm x121 L)/ ( 5.15 atm x 293 k) = 131.43 L